Решите уравнение х(х^2 - 6х + 5) = 12(х - 5).

X( x^2 - 6x + 5) = 12( x - 5) x( x - 5)(x - 1) - 12( x - 5) = 0 ( x - 5)( x(x - 1) - 12) = 0 ( x - 5)( x^2 - x - 12) = 0 x - 5 = 0 x = 5 x^2 - x - 12 = 0 d = b^2 - 4ac = 1 + 48 = 49 = 7^2 x1 = ( 1 + 7)/ 2 = 4 x2 = ( 1 - 7) / 2 = - 3 ответ: x1 = 4, x2 = - 3, x3 = 5.

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